Submission #3043912


Source Code Expand

import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    n,m = LI()
    s,t = LI()
    e = collections.defaultdict(list)
    for _ in range(m):
        u,v,d = LI()
        e[u].append((v,d))
        e[v].append((u,d))

    def search(s,t):
        d = collections.defaultdict(lambda: [inf, 0])
        d[s] = [0, 1]
        q = []
        heapq.heappush(q, (0, s))
        v = collections.defaultdict(bool)
        while len(q):
            k, u = heapq.heappop(q)
            if v[u]:
                continue
            v[u] = True

            uc = d[u][1]

            for uv, ud in e[u]:
                if v[uv]:
                    continue
                vd = k + ud
                if d[uv][0] > vd:
                    d[uv] = [vd, uc]
                    heapq.heappush(q, (vd, uv))
                elif d[uv][0] == vd:
                    d[uv][1] += uc

        return d

    d1 = search(s,t)
    d2 = search(t,s)
    rd = d1[t][0]
    kk = rd / 2.0

    r = d1[t][1] ** 2
    for k in list(d1.keys()):
        t,c = d1[k]
        if t > kk:
            continue
        if t == kk:
            if d2[k][0] == t:
                r -= c**2 * d2[k][1]**2
            continue

        for uv, ud in e[k]:
            if d2[uv][0] >= kk or t + ud + d2[uv][0] != rd:
                continue
            r -= c**2 * d2[uv][1]**2

    return r




print(main())

Submission Info

Submission Time
Task E - Avoiding Collision
User iehn
Language PyPy3 (2.4.0)
Score 0
Code Size 2082 Byte
Status WA
Exec Time 2110 ms
Memory 141668 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 0 / 700
Status
AC × 4
AC × 10
WA × 4
TLE × 8
Set Name Test Cases
Sample sample01.txt, sample02.txt, sample03.txt, sample04.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, sample01.txt, sample02.txt, sample03.txt, sample04.txt
Case Name Status Exec Time Memory
01.txt AC 1532 ms 131812 KB
02.txt AC 1984 ms 123740 KB
03.txt WA 1921 ms 126432 KB
04.txt WA 1893 ms 129312 KB
05.txt AC 1900 ms 124388 KB
06.txt WA 1666 ms 124004 KB
07.txt TLE 2110 ms 128988 KB
08.txt AC 897 ms 116704 KB
09.txt TLE 2036 ms 130400 KB
10.txt WA 1892 ms 141668 KB
11.txt AC 1889 ms 121828 KB
12.txt AC 1774 ms 134984 KB
13.txt TLE 2110 ms 125784 KB
14.txt TLE 2110 ms 129500 KB
15.txt TLE 2110 ms 124768 KB
16.txt TLE 2110 ms 128484 KB
17.txt TLE 2110 ms 128348 KB
18.txt TLE 2104 ms 129500 KB
sample01.txt AC 283 ms 64236 KB
sample02.txt AC 286 ms 64364 KB
sample03.txt AC 292 ms 64236 KB
sample04.txt AC 295 ms 64364 KB