Submission #3043970


Source Code Expand

import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    n,m = LI()
    s,t = LI()
    e = collections.defaultdict(list)
    for _ in range(m):
        u,v,d = LI()
        e[u].append((v,d))
        e[v].append((u,d))

    def search(s,t):
        d = collections.defaultdict(lambda: [inf, 0])
        d[s] = [0, 1]
        q = []
        heapq.heappush(q, (0, s))
        v = collections.defaultdict(bool)
        while len(q):
            k, u = heapq.heappop(q)
            if v[u]:
                continue
            v[u] = True

            uc = d[u][1]

            for uv, ud in e[u]:
                if v[uv]:
                    continue
                vd = k + ud
                if d[uv][0] > vd:
                    d[uv] = [vd, uc]
                    heapq.heappush(q, (vd, uv))
                elif d[uv][0] == vd:
                    d[uv][1] += uc

        return d

    d1 = search(s,t)
    d2 = search(t,s)
    rd = d1[t][0]
    kk = rd / 2.0

    r = d1[t][1] ** 2
    for k in list(d1.keys()):
        t,c = d1[k]
        if t > kk:
            continue
        if t == kk:
            if d2[k][0] == t:
                r -= c**2 * d2[k][1]**2
            continue

        for uv, ud in e[k]:
            if d2[uv][0] >= kk or t + ud + d2[uv][0] != rd:
                continue
            r -= c**2 * d2[uv][1]**2

    return r % mod




print(main())

Submission Info

Submission Time
Task E - Avoiding Collision
User iehn
Language PyPy3 (2.4.0)
Score 0
Code Size 2088 Byte
Status TLE
Exec Time 2098 ms
Memory 141668 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 0 / 700
Status
AC × 4
AC × 21
TLE × 1
Set Name Test Cases
Sample sample01.txt, sample02.txt, sample03.txt, sample04.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, sample01.txt, sample02.txt, sample03.txt, sample04.txt
Case Name Status Exec Time Memory
01.txt AC 1392 ms 135396 KB
02.txt AC 1734 ms 123740 KB
03.txt AC 1719 ms 126432 KB
04.txt AC 1724 ms 129248 KB
05.txt AC 1753 ms 124388 KB
06.txt AC 1520 ms 124512 KB
07.txt AC 1890 ms 128988 KB
08.txt AC 817 ms 116704 KB
09.txt AC 1889 ms 131168 KB
10.txt AC 1621 ms 141668 KB
11.txt AC 1716 ms 121828 KB
12.txt AC 1599 ms 134884 KB
13.txt AC 1975 ms 128220 KB
14.txt AC 2000 ms 129500 KB
15.txt TLE 2098 ms 126176 KB
16.txt AC 1892 ms 128348 KB
17.txt AC 1973 ms 128408 KB
18.txt AC 1869 ms 129752 KB
sample01.txt AC 273 ms 64364 KB
sample02.txt AC 274 ms 64364 KB
sample03.txt AC 272 ms 64236 KB
sample04.txt AC 272 ms 64364 KB