Submission #3607803


Source Code Expand

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define ll long long
#define rep(i,l,r)for(ll i=(l);i<(r);i++)
#define INF ((1LL<<62)-(1LL<<31))
#define MOD 1000000007

//プラキュー(二分ヒープ)(優先度変更ありバージョン)
ll heapN,heap[1<<20],heapinv[1<<20];
int PQhikaku(int i,int j);//jの方が優先度が高いならtrueを返す
void PQchange(int n);
void heap_utod(int n){
	if(2*n>heapN)return;
	int rflag=(2*n+1<=heapN)&&(PQhikaku(2*n,2*n+1));
	if(PQhikaku(n,2*n+rflag)){
		ll temp=heap[2*n+rflag];
		heap[2*n+rflag]=heap[n];
		heap[n]=temp;
		heapinv[heap[n]]=n;
		heapinv[heap[2*n+rflag]]=2*n+rflag;	
		heap_utod(2*n+rflag);
	}
}
void heap_dtou(int n){
	if(n==1||PQhikaku(n,n/2))return;
	ll temp=heap[n];
	heap[n]=heap[n/2];
	heap[n/2]=temp;
	heapinv[heap[n]]=n;
	heapinv[heap[n/2]]=n/2;
	heap_dtou(n/2);
}
ll PQpop(){
	ll rr=heap[1];
	heapinv[heap[1]]=0;
	heap[1]=heap[heapN--];
	heapinv[heap[1]]=1;
	heap_utod(1);
	return rr;
}
void PQpush(ll n){
	heap[++heapN]=n;
	heapinv[heap[heapN]]=heapN;
	heap_dtou(heapN);
}


//辺の情報を個別に持つタイプ
typedef struct edge{ll s,g,c;}E;
typedef struct graph{
	ll vcnt,ecnt;
	E  e[400010];//適宜変える
	ll id[100010];//適宜変える
}G;
int esort(const void*a,const void*b){
	E*p=(E*)a,*q=(E*)b;
	if((*p).s<(*q).s)return -1;
	if((*p).s>(*q).s)return  1;
	if((*p).g<(*q).g)return -1;
	return 1;
}

G g;
ll s,t;
void readgraph(){
	//適宜変える
	ll n,m;
	scanf("%lld%lld",&n,&m);
	scanf("%lld%lld",&s,&t);
	s--,t--;
	rep(i,0,m){
		ll x,y,c;
		scanf("%lld%lld%lld",&x,&y,&c);
		x--,y--;
		g.e[2*i].s=x;
		g.e[2*i].g=y;
		g.e[2*i].c=c;
		g.e[2*i+1].s=y;
		g.e[2*i+1].g=x;
		g.e[2*i+1].c=c;
	}
	g.vcnt=n;
	g.ecnt=2*m;
	qsort(g.e,g.ecnt,sizeof(E),esort);

	int p=0;
	rep(i,0,g.vcnt){
		while(p<g.ecnt&&g.e[p].s<i)p++;
		g.id[i]=p;
	}
	g.id[g.vcnt]=g.ecnt;//一応番兵
}



//早い方のダイクストラ
//グラフと始点を引いて各点への最短距離・最短経路を返す
//辺は有向
//プラキューを使う
//O((E+V)logV)
ll daikusutorappp[1<<20];
ll daikusutora222[1<<20];
void daikusutora2(G g,ll s){
	rep(i,0,g.vcnt)daikusutorappp[i]=i==s?0:INF;
	rep(i,0,g.vcnt)daikusutora222[i]=i==s?1:0;//追加
	rep(i,0,g.vcnt)PQpush(i);
	while(heapN){
		ll mv=PQpop();
		for(ll t=g.id[mv];g.e[t].s==mv;t++){
			if(daikusutorappp[g.e[t].g]>daikusutorappp[mv]+g.e[t].c){
				daikusutorappp[g.e[t].g]=daikusutorappp[mv]+g.e[t].c;
				daikusutora222[g.e[t].g]=daikusutora222[mv];//追加
				PQchange(g.e[t].g);
			}else if(daikusutorappp[g.e[t].g]==daikusutorappp[mv]+g.e[t].c){//追加
				daikusutora222[g.e[t].g]+=daikusutora222[mv];//追加
				daikusutora222[g.e[t].g]%=MOD;
			}
		}
	}
}
int PQhikaku(int i,int j){return daikusutorappp[heap[i]]>daikusutorappp[heap[j]];}
void PQchange(int n){if(heapinv[n])heap_dtou(heapinv[n]);}


ll scost[100010],scnt[100010];
ll tcost[100010],tcnt[100010];
int main(){
	readgraph();
	daikusutora2(g,s);
	rep(i,0,g.vcnt){
		scost[i]=daikusutorappp[i];
		scnt[i]=daikusutora222[i];
	}
	daikusutora2(g,t);
	rep(i,0,g.vcnt){
		tcost[i]=daikusutorappp[i];
		tcnt[i]=daikusutora222[i];
	}
	
	ll d=scost[t];
	ll ans=scnt[t]*tcnt[s]%MOD;
	rep(i,0,g.vcnt)if(scost[i]*2==d)ans=(ans-scnt[i]*tcnt[i]%MOD*tcnt[i]%MOD*scnt[i]%MOD+MOD)%MOD;
	rep(i,0,g.ecnt){
		if(scost[g.e[i].s]+g.e[i].c+tcost[g.e[i].g]==d&&scost[g.e[i].s]*2<d&&tcost[g.e[i].g]*2<d){
			ans=(ans-scnt[g.e[i].s]*tcnt[g.e[i].g]%MOD*tcnt[g.e[i].g]%MOD*scnt[g.e[i].s]%MOD+MOD)%MOD;
		}
	}
	printf("%lld\n",ans);
	return 0;
}

Submission Info

Submission Time
Task E - Avoiding Collision
User kyopro_friends
Language C (GCC 5.4.1)
Score 700
Code Size 3690 Byte
Status AC
Exec Time 270 ms
Memory 30428 KB

Compile Error

./Main.c: In function ‘readgraph’:
./Main.c:69:2: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
  scanf("%lld%lld",&n,&m);
  ^
./Main.c:70:2: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
  scanf("%lld%lld",&s,&t);
  ^
./Main.c:74:3: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
   scanf("%lld%lld%lld",&x,&y,&c);
   ^

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 700 / 700
Status
AC × 4
AC × 22
Set Name Test Cases
Sample sample01.txt, sample02.txt, sample03.txt, sample04.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, sample01.txt, sample02.txt, sample03.txt, sample04.txt
Case Name Status Exec Time Memory
01.txt AC 255 ms 30300 KB
02.txt AC 262 ms 30300 KB
03.txt AC 262 ms 30300 KB
04.txt AC 265 ms 30300 KB
05.txt AC 255 ms 30300 KB
06.txt AC 200 ms 30336 KB
07.txt AC 257 ms 30300 KB
08.txt AC 136 ms 28324 KB
09.txt AC 256 ms 30300 KB
10.txt AC 252 ms 30300 KB
11.txt AC 270 ms 30300 KB
12.txt AC 254 ms 30300 KB
13.txt AC 245 ms 30300 KB
14.txt AC 259 ms 30300 KB
15.txt AC 261 ms 30428 KB
16.txt AC 253 ms 30300 KB
17.txt AC 252 ms 30300 KB
18.txt AC 270 ms 30300 KB
sample01.txt AC 8 ms 22656 KB
sample02.txt AC 9 ms 22656 KB
sample03.txt AC 8 ms 22656 KB
sample04.txt AC 8 ms 22656 KB